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StrKT 10 (P414663)

Mathematical, Old Babylonian, Uruk · c. 1900 BCE–1600 BCE

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DesignationStrKT 10
IDP414663
Museum no.BNUS 367
CollectionBibliothèque Nationale et Universitaire de Strasbourg, Strasbourg, France
LanguageAkkadian
PeriodOld Babylonian · c. 1900 BCE–1600 BCE
GenreMathematical
Find spotUruk (mod. Warka)
Coordinates31.3234, 45.6395

Transliteration (ATF)

From Open Richly Annotated Cuneiform Corpus (ORACC) · CC BY-SA 3.0 (ORACC default); per-file JSON license fields say: This data is released under the CC0 license (133618)

Machine draft. The right-hand column is machine English from ixmon/atf-to-english (atf-en-t5base-F, 2026-10-17), generated line by line from the transliteration. It is unreviewed and is not a scholarly translation.

LineATFMachine English (draft)
o
1SAG.KI.GU₄ SAG.KI.GU₄ i-na ŠA₃ 2 I₇-MEŠ 13.03 A.ŠA₃ AN.<NA>A bull's head (and) a cow from 2 canals. 13 03, the area of an eagle.
222.57 A.ŠA₃ <KI>-2 ⸢IGI⸣ 3-GAL₂ US₂ KI.<TA> i-⸢na⸣22 57, the lower length to the lower width.
3US₂ AN.NA ša SAG AN.NA UGU DAL DIRIThe length of the lead, which is equal to the width, exceeds the diagonal.
4u₃ DAL UGU SAG KI.TA DIRI GAR.GAR 36and the upper side on the top adjacent to the lower width: a total of 36.
5US₂-NE.NE SAG-MEŠ u₃ DAL EN.NAMWhat are the length, width, and diagonal?
6ZA.E KI₃.DA.ZU.DE₃ KI₃.DA.ZU.DE₃ 1 u₃ 3 HE₂.GARYou: perform the kidzû-ritual. You will put down 1 and 3.
71 u₃ 3 GAR.GAR 4 IGI 4 DU₈-ma 15Solve the reciprocal of 4 so that (it gives) 15.
815 a-na 36 NIM 9 IN.SUM 9 a-naMultiply 0;15 by 36. It gives 9. Add 9 to
91 NIM 9 IN.SUM 9 a-na 3 NIM 27Multiply 9 by 3. It gives 27.
109 ša SAG AN.NA UGU DAL DIRI9 (items): the capital of the lead exceeds the width.
1127 ša DAL UGU DAL KI.TA DIRIThe 27th, the upper side is elevated above the lower side.
12IGI 1 DU₈ 1 a-na 13.03 NIMreciprocal 1
1313.03 IN.SUM IGI 3 DU₈ 20 a-naSolve the reciprocal of 3. Multiply 20 by 0;20.
1422.57 NIM 7.39 IN.SUM0;22 57, the reciprocal of 7 39, was given.
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113.03 UGU 7.39 EN.NAM DIRIWhat does 13 03 exceed 7 39?
25.24 DIRI 1 u₃ 3 GAR.GAR 40;05 24, the diagonal, 1 and 3, the dividing line: 4.
31/2 4 GAZ 2 IGI 2 DU₈ 30 a-na 5.24 <NIM>Multiply 1/2 by 4 00. The reciprocal of 2 is 2. You will see 2. Add 0;30 to <5 24>.
42.42 IN.SUM(MA) la₃ LUL 2.42 la₃ DU₈he will give 2;42. He will not lie down. 2 42 is not broken.
5EN.NAM a-na 2.42 HE₂.GAR ša 9 IN.SUMWhat should I put down to 2 42? It gives 9 00.
63.20 HE₂.GAR IGI 3.20 DU₈ 18 IN.SUMSolve the reciprocal of 3;20. It gives 0;18.
718 a-na 1 NIM 18 US₂ AN.NA 18Multiply 18 by 1. The length is 18. The lead is 18.
8a-na 3 NIM 54 US₂ KI.<TA>Multiply by 3, the upper length, 54 (rods), the lower length.
91/2 36 GAZ 17 a-na 1.12 NIMHalf a shekel: 36 will come up. Multiply 17 by 1;12, the constant.
1021.36 i-na 36 A.ŠA₃ DU₈ 14.24Multiply 0;21 36 by 36 00, the area. You will see 14 24.
11IGI 1.12 US₂ DU₈ 50 a-na 14.24 NIMreciprocal 1 12
1212 IN.SUM 12 a-na 36 DAH-ma 48Multiply 12 by 36, so that (it is) 48.
1348 SAG AN.NA 12 a-na 27 DAH0;48, the capital of the lead. Add 12 to 27.
1439 DAL 12 SAG KI.TA IN.SUM39, the long side, 12 (cubits), the lower width he gave.

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Cite the original edition and translator. Page generated by Unread Atlas from the public corpus export of 2026-10-18.