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StrKT 07 (P414660)
Mathematical, Old Babylonian, Uruk · c. 1900 BCE–1600 BCE
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| Designation | StrKT 07 |
|---|---|
| ID | P414660 |
| Museum no. | BNUS 363 |
| Collection | Bibliothèque Nationale et Universitaire de Strasbourg, Strasbourg, France |
| Language | Akkadian |
| Period | Old Babylonian · c. 1900 BCE–1600 BCE |
| Genre | Mathematical |
| Find spot | Uruk (mod. Warka) |
| Coordinates | 31.3234, 45.6395 |
Transliteration (ATF)
From Open Richly Annotated Cuneiform Corpus (ORACC) · CC BY-SA 3.0 (ORACC default); per-file JSON license fields say: This data is released under the CC0 license (133618)
Machine draft. The right-hand column is machine English from ixmon/atf-to-english (atf-en-t5base-F, 2026-10-17), generated line by line from the transliteration. It is unreviewed and is not a scholarly translation.
| Line | ATF | Machine English (draft) |
|---|---|---|
| o | ||
| 1 | A.ŠA₃ 2 IB₂.SI₈ GAR.GAR-ma 16.40 IB₂.SI₈ 2/3 IB₂.SI₈ | Solve the reciprocal of 2 00 00, the square-side, so that 16 40 00. |
| 2 | 10 i-na IB₂.SI₈ TUR BA.ZI IB₂.SI₈ EN.NAM ZA.E KI₃.DA.ZU.DE₃ KI₃.DA.ZU.DE₃ | You take away 0;10 from the small square-side. What is the square side? You, when you are to do it, you will do it. |
| 3 | 10 DU₇.DU₇ 1.40 IN.SUM 1.40 i-na 16.40 ZI-ma | Combine 0;10, so that it gives 1;40. Take away 1 40 from 16;40 so that (it gives) 1;20. |
| 4 | 15 IN.SUM 1 DU₇.DU₇-ma 1 IN.SUM 40 DU₇.DU₇-ma 26.40 | Solve the reciprocal of 0;15, so that 1 gives 1. Solve (the reciprocal) of 40 so that 26;40. |
| 5 | 1 u₃ 26.40 GAR.GAR-ma 1.26.40 IN.SUM 1.26.40 a-na 15 NIM | Sum 1 and 0;26 40, so that it gives 1;26 4. Multiply [1;26] 40 by 15 00. |
| 6 | 21.40 IN.SUM 40 a-na 10 NIM-ma 6.40 IN.SUM | Multiply 0;40 by 10, so that it gives 6;40. |
| 7 | 6.40 DU₇.DU₇-ma 44.26.40 IN.SUM 44.26.40 | Combine 6;40 so that it gives 44;26 40. |
| 8 | a-na 21.40 DAH-ma 22.24.26.40 IN.SUM | Add to 21;40 so that it gives 22 24;26 40. |
| 9 | 22.24.26.40-E 36.40 IB₂.SI₈ 6.40 ša tu-uš-ta-ki-lu | 22 24 26 40 squares 36 40 |
| 10 | a-na 36.40 DAH-ma 43.20 IN.SUM mi-nam a-na 1.26.40 HE₂.GAR | Add to 36;40 so that it gives 43;20. What should I add to 1;26 40? |
| 11 | ša 43.20 IN.SUM 30 šu-ku-un 30 a-na 1 NIM-ma 30 IB₂.SI₈ GU.LA | Multiply 0;30 by 1, so that the square-side is 30. |
| 12 | 30 a-na 40 NIM-ma 20 IN.SUM 10 i-na 20 ZI-ma 10 IB₂.SI₈ TUR.RA | Multiply 0;30 by 40, so that it gives 20. Take away 10 from 20, so that the small square-side is 10. |
| 13 | A.ŠA₃ 2 IB₂.SI₈ GAR.GAR-ma 37.05 IB₂.SI₈ 2/3 IB₂.SI₈ | Solve the reciprocal of 2 00, the square-side, so that (it gives) 37 05 00. |
| 14 | 10 a-na IB₂.SI₈ GU.LA BI₂.DAH 5 a-na IB₂.SI₈ TUR.RA BI₂.DAH | Multiply 0;10 by the square-side of a shoulder. You will see 5 by the small side. |
| 15 | IB₂.SI₈ EN.NAM ZA.E KI₃.DA.ZU.DE₃ KI₃.DA.ZU.DE₃ 10 DU₇.DU₇-ma 1.40 IN.SUM | What is the square-side? You: solve the reciprocal of 0;10, so that it gives 1;40. |
| 16 | 5 DU₇.DU₇ 25 IN.SUM 1.40 u₃ 25 GAR.GAR-ma 2.05 IN.SUM | Multiply 0;05 by 25, so that it gives 2 05. |
| 17 | 2.05 i-na 37.05 ZI-ma 35 IN.SUM | Multiply 2 05 by 37 05, so that it gives 35. |
| 18 | 1 DU₇.DU₇-ma 1 IN.SUM 40 DU₇.DU₇-ma 26.40 | Combine 1, so that it gives 1. Combine 0;40, so that (it gives) 26 40. |
| 19 | 1 u₃ 26.40 GAR.GAR-ma 1.26.40 IN.SUM 1.26.40 | Put down 1 and 0;26 40, so that it gives 1 26 40. |
| 20 | a-na 35 NIM-ma 50.33.20 IN.SUM 10 a-na 1 NIM 10 ⸢IN⸣.[SUM] | Multiply by 0;35 so that it gives 50 33 20. Add 10 to 1. It gives 10 00. |
| 21 | 40 a-na 5 NIM-ma 3.20 IN.SUM 10 u₃ 3.20 GAR.GAR-ma | Multiply 0;40 by 5, so that it gives 3;20. Combine 10 and 3, so that (it gives) 3. |
| 22 | 13.20 IN.SUM 13.20 DU₇.DU₇ 2.57.46.40 <IN.SUM> | Solve the reciprocal of 0;13 20, so that you see 2;57 46 40. |
| r | ||
| 1 | 2.57.46.40 a-na 50.33.20 DAH-ma | Add 2 57 46 40 to 50 33 20 and |
| 2 | 53.31.06.40 IN.SUM 53.31.06.40-E 56.40 IB₂.SI₈ | Multiply 0;53 31 06 40 so that it gives 5;31 06 40. The square-side of 5;41 40 is 56;40. |
| 3 | 13.20 i-na 56.40 ZI-ma 43.20 IN.SUM | Multiply 0;13 20 by 56 40, so that it gives 43;20. |
| 4 | mi-nam a-na 1.26.40 HE₂.GAR ša 43.20 i-na-di-nam | What should I multiply by 1;26 40, the dividing line of 43;20? |
| 5 | 30 šu-ku-un 30 a-na 1 NIM-ma 30 IN.SUM 10 a-na 30 DAH-ma | Multiply 0;30 by 1, so that it gives 30. Add 10 to 30, so that (it gives) 30. |
| 6 | 40 IB₂.SI₈ GU.LA 30 a-na 40 NIM 20 IN.SUM 5 a-na 20 DAH-ma | Multiply 0;40, the square-side of a trench. You multiply 30 by 40. You give 20. Add 5 to 20, so that (it gives) 20. |
| 7 | 25 IB₂.SI₈ TUR.RA i-na-di-nam | 25 small squares he will give. |
| 8 | A.ŠA₃ 2 IB₂.SI₈ GAR.GAR-ma 52.05 IB₂.SI₈ 2/3 IB₂.[SI₈] | Solve the reciprocal of 2 00 00, the square-side, so that 0;52 05 00 will result. |
| 9 | 20 a-na IB₂.SI₈ GU.LA BI₂.DAH 5 a-na IB₂.SI₈ TUR.RA [BI₂].⸢DAH⸣ | Add 0;20 to the square-side of a small square. |
| 10 | IB₂.SI₈ EN.NAM ZA.E KI₃.DA.ZU.DE₃ KI₃.DA.ZU.DE₃ 20 DU₇.DU₇-ma 6.40 | What is the square-side? You: solve the reciprocal of 0;20, so that 6;40. |
| 11 | 5 DU₇.DU₇-ma 25 IN.SUM 6.40 u₃ 25 GAR.GAR-ma | Multiply 0;05 so that it gives 25. You put 6;40 and 25. |
| 12 | 7.05 IN.SUM 7.05 i-na 52.05 ZI-ma 45 IN.SUM | Multiply 7 05 by 52 05, so that it gives 45. |
| 13 | 1 DU₇.DU₇-ma 1 IN.SUM 40 DU₇.DU₇ 26.40 IN.SUM | Combine 1, so that it gives 1. Combine 0;40. It gives 26 40. |
| 14 | 1 u₃ 26.40 GAR.GAR-ma 1.26.40 IN.SUM 1.26.40 | Put down 1 and 0;26 40, so that it gives 1 26 40. |
| 15 | a-na 45 NIM-ma 1.05 IN.SUM 20 u₃ 1 DU₇.DU₇-ma 20 | Multiply by 0;45 so that it gives 1;05. Combine 20 and 1, so that (it gives) 20. |
| 16 | 40 u₃ 5 DU₇.DU₇-ma 3.20 IN.SUM 20 u₃ 3.20 GAR.GAR-ma | You combine 0;40 and 5, so that it gives 3;20. You put 20 and [3;20]. |
| 17 | 23.20 IN.SUM 23.20 DU₇.DU₇-ma 9.04.26.40 IN.SUM | Solve the reciprocal of 23;20 so that it gives 9 04;26 40. |
| 18 | 9.04.26.40 a-na 1.05 DAH-ma 1.14.04.26.40 IN.SUM | Add 9 04;26 40 to 1 05, so that it gives 1 14;04 26 40. |
| 19 | 1.14.04.26.40-E 1.06.40 IB₂.SI₈ 23.20 i-na 1.06.40 ZI-ma | 1 14 14 26 40 squares 1 06 40. Take away 23;20 from 1 06;40 and |
| 20 | 43.20 IN].SUM mi-nam a-na 1.26.40 lu-uš-ku-un | What should I put to 1 26 40? |
| 21 | ša 43.20 IN.SUM 30 HE₂.GAR 30 a-na 1 NIM 30 IN.SUM | Multiply 0;30 by 1. It gives 30. |
| 22 | 20 a-na 30 DAH-ma 50 IB₂.SI₈ GU.LA 30 a-na 40 NIM | Add 20 to 30, so that the square-side is 50. Multiply 30 by 40. |
| 23 | 20 IN.SUM 5 a-na 20 DAH-ma 25 IB₂.SI₈ TUR.RA; IN.SUM | Multiply 5 by 20, so that it gives 25. The small square-side is 0;25. |
Sources & licences
- Cuneiform Digital Library Initiative · CDLI: reuse of catalogue/transliteration data with citation of CDLI; images restricted (not fetched) · Cuneiform Digital Library Initiative (CDLI), https://cdli.earth/ ; cite CDLI and the P-number
- Open Richly Annotated Cuneiform Corpus (ORACC) · CC BY-SA 3.0 (ORACC default); per-file JSON license fields say: This data is released under the CC0 license (133618) · ORACC project editions, https://oracc.museum.upenn.edu/ ; cite the individual project (see texts.extra_json.project)
Cite the original edition and translator. Page generated by Unread Atlas from the public corpus export of 2026-10-18.